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$\begingroup$ @TalorT: At $1.12$ the table gives $0.8686$. At $1.13$ it gives $0.8708$. Interpolating linearly, we get that the value should be about $0.8686+(9/10)(0.8708-0.8686)$. By the way, fine-grained results are often not worthwhile, since in real situations our random variable is only approximately normal, so a high precision answer may not be scientifically valid.
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